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crash
15th November 2005, 05:07 PM
For those who like staking systems this is about as good as they get:

The concept behind this system is that in the long run two events of roughly equal probability will happen roughly the same number of times. This system depends on this happening in the short run. The more money you wish to put up, the longer into the long run you can afford to go, thus increasing your odds of a winning session, but at the risk of losing more.

1. Start by writing on a piece of paper ten 1s in a row (1 1 1 1 1 1 1 1 1 1). Each number will represent a betting unit. When all numbers have been crossed off the paper you will have won 10 units.
2. For each bet wager the sum of the number on the left and the number on the right, unless there is only one number left in which case you bet that number.
3. If you win cross off both numbers.
4. If you lose place the sum at the end on the right.
5. If the bankroll you decided to risk at the beginning is not enough to bet the sum of the left and right numbers then:
5A. If your bankroll can cover the number on the left then wager that. If you win then cross off the left number. If you lose then add to the left number what you lost.
5B. If your bankroll can not cover the number on the left then bet whatever is left of your bankroll. If you win then deduct from the number on the left what you won.
6. Keep repeating these steps until you either cross off all numbers or exhaust the bankroll you decided initially to risk.

Here is an example:
You start with 1 1 1 1 1 1 1 1 1 1.
You then wager two units and win, cross off the 1 on the left and right, leaving 1 1 1 1 1 1 1 1.
You then wager another two units and lose, adding a 2 to the right, leaving 1 1 1 1 1 1 1 1 2.
You then wager three units (1+2) and lose again, adding a 3 to the right, leaving 1 1 1 1 1 1 1 1 2 3.
You then wager four units (1+3) and win, crossing off the 1 on the left and the 3 on the right, leaving 1 1 1 1 1 1 1 2 .

The theory is that by crossing off two numbers for a win and adding only one for a loss you will eventually cross off all the numbers.

Cheers.

Dirk Gently
15th November 2005, 08:55 PM
Quote
"2. For each bet wager the sum of the number on the left and the number on the right, unless there is only one number left in which case you bet that number. "

Isn't this system more for 50% strike rate/returns? Should you bet to WIN the sum of the two numbers and add the lost WAGER to the end of the line? Then at the end of the sequence your profit would be ten units?

Bhagwan
16th November 2005, 09:25 AM
This is sometimes called the Fabacci method .(famous Italian mathamatician)
The idea is to add both ends together as indicated , but the amount crossed off should be related to the odds .
E.g. odds 1/1 cross off one number from each end ( as mentioned by Crash)
2/1 cross off 2 numbers from each end.
5/1 cross off 5 numbers from each end.ect
Before adding the 2 ends again.

It can work, so as long ones run of outs is not too sevear.
One needs a cut off point where one says enough is enough .
Then start again.

Mark
16th November 2005, 09:41 AM
An old roulette method for backing the even money shots.

crash
16th November 2005, 09:50 AM
From 'The Winner's Guide to Casino Gambling' by Edwin Silberstang. Silberstang notes that it is also called the D'Alembert or Alembert system.

Put it up out of possible interest to those interested in progressive staking [not this boy]. Easily adaptable for horse racing if you think in units won or lost.