View Full Version : Arb
Benny
18th May 2009, 05:29 PM
if I back #8 in race 8 at Albion Pk on the tote for $58 @ a $170 and lay it for $40 @ $2.50 I'll make a small profit.
Shaun
18th May 2009, 05:40 PM
where is it $170
Benny
18th May 2009, 05:58 PM
it's meant to be $1.70 not $170, sorry
Shaun
18th May 2009, 06:14 PM
If the lay price is higher than the back price no profit possible.
Benny
18th May 2009, 06:27 PM
I'm new at trading, so how do I make a profit.
goty0405
18th May 2009, 06:56 PM
Back price ALWAYS must be higher than lay price. The bigger the difference the bigger the profit. Follow the example...
Step 1: Back $100 @ 3.0
If it wins = +200
If it loses = -100
Step 2: Lay $100 @ 2.0
If it wins = -100
If it loses = +100
Combined
If it wins = 100 (200 - 100)
If it loses = 0 (-100 + 100)
So there you have a "win:break-even" situation. If the horse wins you make $100, if it loses you break even. If you want to take trading one step further you can spread that winning situation around so that you make a smaller profit on each horse. You do this by laying a little extra.
The formula to figure out how much to lay is:
AmountToLay = CurrentPossibleProfitIfHorseWins / CurrentLayOdds
So in the above situation...
AmountToLay = 100 / 2.0 = 50
Step 3: Spread the risk (lay $50 @ 2.0)
If it wins = -50
If it loses = +50
Overall traded result
If it wins = 50 (200 - 100 - 50)
if it loses = 50 (-100 + 100 + 50)
A guaranteed $50 no matter which horse wins!
Benny
18th May 2009, 07:40 PM
Thanks. It explains it lot.
Now here's a another bet from the same race.
I'm not sure if this correct using the example
#1 to win $50 @ $3.90 = $195
#1 to lose $50 @ $2.50 = $125
Overall result
If it wins $50-(100-50)
If it loses $50-(100+50)
Shaun
18th May 2009, 08:06 PM
Take a look at this
Benny
18th May 2009, 08:10 PM
Just out of interest of the 2 bets. #8 won and #1 lost.
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