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BJ 12th January 2005 10:02 PM

Do the bank????
 
If you are betting a percentage of the bank, it will never run dry....... Only if you bet 100% of the bank can you wipe it out otherwise your bets just get smaller and smaller until it is not worth betting, but it will never run dry.....

Bhagwan 12th January 2005 10:46 PM

Longest run of expected Run of outs based on 10,000
This question has come up a number of times before.
So, here it is again.


10%-65
15%-42
20%-31
25%-24
30%-20
35%-16
40%-14
45%-12
50%-10
60%-9
70%-5
80%-5
90%-3

system 13th January 2005 01:37 AM

guys i dont like this run of outs stuff cause 1 lousy winner breaks up the outs so 24 out 1 win 24 out i think this is bad news.yes ive had a couple of drinks but still 1 win breaks the run of outs but doesnt put your bank back in the black,or save you from going bust.

DR RON 13th January 2005 05:32 PM

Instead of worrying about runs of outs, would anyone be able to produce figures for expected runs of winners???

Would it be just as likely that in 10000 races the longest run of outs would be followed by the longest run of winners???

Just trying to keep positive.

woof43 13th January 2005 06:53 PM

Clumpiness of Wins
 
Dr. Ron you have maybe touched on one of the most important aspect of wagering that is called Deviation.

Once you get to your second bet in any wagering situation your finances fall into one of three categories:
1. YOU HAVE A PROFIT.
2. YOU HAVE A LOSS.
3. YOU ARE EVEN.
The key question is: if I am in a losing or winning streak, does the probability of a reversal of this trend increase or decrease, as my number of bets increases?
Take a look below at this insightfull chart on deviation and coin flipping.
First, when you flip a coin 10 times, you'll get one of 1024
possible combinations of heads and tails. Assuming the coin is
unbiased, each combination is as likely as any other. Your
0110001011 is no more or less apt to occur than 1010101010 or
1111111111. Although yours doesn't seem peculiar in any way, it's
still just one out of 1024 equally probable combinations and
therefore has a chance of 1/1024 -- just like any of the others.

Second, when you flip a coin 10 times, the "expected" number of
heads and tails is five each. But "expected" is a statistical
term, and by no means tells what will actually happen. In fact,
based purely on the ways any given number of heads and tails can
be arranged, you can find the following probabilities:
===========================
Chance of various numbers
of heads in 10 flips
no of ways probability
heads
0 1 0.098%
1 10 0.977%
2 45 4.394%
3 120 11.719%
4 210 20.508%
5 252 24.609%
6 210 20.508%
7 120 11.719%
8 45 4.395%
9 10 0.977%
10 1 0.098%
===========================

The list shows that, in 10 flips, five heads can occur most often
-- 252 out of 1024 ways. This is why five is the "expected"
value. But four or six heads aren't all that unlikely, with 210
ways each. And so on, along the line. There's nothing mystical
behind these figures. Just a matter of counting arrangements.
Zero heads can occur one way: 0000000000. One can occur 10 ways:
1000000000, 0100000000, 0010000000, 0001000000, 0000100000,
0000010000, 0000001000, 0000000100, 0000000010, and 0000000001.
You can try it yourself with other numbers of heads, but the
enumerations get messy so you might prefer to take me at my word.

Of course, what the vast majority of people will fail to see is the whole truth about the fact, that the most probable outcome of ten flips of a coin is 5 heads and 5 tails.
An important aspect of DEVIATION IS THAT WHILE YOU ARE EXPERIENCING A POSITIVE DEVIATION, you can and will have LOSING STREAKS. Of course the same principle applies to what will happen during a NEGATIVE DEVIATION. THE MOST IMPORTANT ISSUE CONFRONTING THE US IS HOW DO YOU COMPENSATE FOR THESE DEVIATIONS, AND IN THE PROCESS MAKE CONSISTENT, PROFITS.
Cheers

Duritz 13th January 2005 07:26 PM

Rosenkrantz and Guildenstern would've wiped out their bank, that's for sure.........

Anyway, the point of my original thingo was trying to work out what was a reasonable percentage of a bank to bet on a system with a strike rate of 20%. System suggested starting out at 1% of bank, sounds good. Even with a run of outs of 31, as bhagwan suggested was the maximum, the bank wouldn't be gone, and even if all of the nightmares that keep system up at night drinking ;P came true - ie 31 losers, 1 winner, 31 losers, 1 winner, 31 losers (and if I hadn't ABANDONED it by then!) then the bank would STILL not be gone. Inglorious, sure, but enduring!

Cheers.
Duritz.

system 14th January 2005 03:17 AM

well said duritz and that coin thing well i might have to read that few times to get the whole meaning(even without a drink).

chiller 14th January 2005 07:55 AM

Strike Rates
 
Hello Duritz,
Maybe you could work out the figure by using the Kelly Method...
Percentage of winner minus the percentage of losers/ divided by average price. So 20 - 80( at say 4.6) = 20-17.39 ( say 3 or 3.5)
For some reason this doesn't look right, so I am sure that I will hear about it.

KennyVictor 14th January 2005 02:42 PM

Quote:
Originally Posted by woof43
THE MOST IMPORTANT ISSUE CONFRONTING THE US IS HOW DO YOU COMPENSATE FOR THESE DEVIATIONS, AND IN THE PROCESS MAKE CONSISTENT, PROFITS.
Cheers


I would imagine that at any point in time there is a statistically safe sized bet (being a proportion of your bank) which would depend only on your strike rate and your average return which would give you a (say) 99.99% chance of never wiping out your bank. This assumes that on level stakes you can come out in front because otherwise I suggest that whatever your betting strategy the bank is going to dissappear eventually.

The answer to the second of the two questions above is simply to select suffiecient winners that you would make a profit on even stakes and the bank will eventually grow.
The answer to the first half may be able to be supplied by a statastician of the calibre of woof43. Given a 20% strike rate and a small positive POT can you tell us what proportion of our bank can be bet to give us a 99.99% chance of never wiping out?
Assuming this figure can be calculated my strategy would be to keep that same size bet during the losing streak because statistics has told us we'll bounce back and increase it in proportion to the growth of the bank as we make a profit (again because we are statistically safe). The other alternative would be to decrease the bet as we encounter a losing streak which I suppose would be safer but would cause you to take longer to bounce back.
Is there such a safe bet? or have I been talking complete bollocks?

KV

woof43 14th January 2005 04:54 PM

basics
 
Hi,
What is the best method of betting or determining your bankroll size? Is it the Kelly or half Kelly? Or something else?
THEORETICALLY: the kelly
AS PRESENTED IN LEADING HANDICAPPING and WAGERING BOOKS: the half kelly.
REALITY: SOMETHING ELSE!!!
The starting point to consistent profits is to identify 20/20 Factors that is 20%POT and a 20% S/R,
Using only 1 or 2 factors on their own or combined, once these 20/20 are identified the kelly criterion provides the best known method to increase your bankroll, but it also carries substantial risk for eroding your bankroll.
So you need to find a balance between Risk and Reward.

The KELLY CRITERION provides for MAXIMUM BANKROLL GROWTH over any extended Profit Determination Periods, it does not provide for MINIMUM RISK. Let me explain:
1. PURE KELLY: REQUIRES YOU TO DETERMINE YOUR POSITIVE EDGE, AND BET THIS PERCENTAGE OF YOUR BANKROLL ON EACH WAGER. The primary problem with this strategy is the uneven payoffs.
2. HYPER-KELLY: REQUIRES YOU TO DETERMINE YOUR POSITIVE EDGE ON EACH BET, DIVIDE THE POSITIVE EDGE BY YOUR ANTICIPATED ODDS, AND WAGER THIS PERCENTAGE OF YOUR BANKROLL ON EACH WAGER. This strategy requires you to make your computations before each race, based upon your estimate of each entrant's probability of winning and the tote board odds. The primary problem with this and the following strategy is the accuracy of your Probability estimates, and their reliance on Tote Board Odds.
3. HALF-KELLY: THE SAME AS HYPER-KELLY, BUT YOU WAGER NO MORE THAN 1/2 THE OPTIMUM KELLY PERCENTAGE.
4. INCREMENTAL FLAT BETTING:IT IS BASED UPON YOUR HISTORIC WIN PERCENTAGE AND AVERAGE ODDS. COMPUTE YOUR POSITIVE EDGE PRIOR TO EACH VISIT TO THE TRACK, AND DIVIDE THE POSITIVE EDGE BY YOUR AVERAGE ODDS. BET NO MORE THAN 1/2 OF THIS PERCENTAGE OF YOUR BANKROLL ON EACH WAGER FOR THE DAY. REPEAT THIS PROCESS EVERY TIME YOU GO TO THE TRACK. This is a method that is more adaptable to Greyhound Betting.
Optimum Method
To find that balance you need to know, when during your betting series the extent of your positive expectation or the negative expectation (win, loss series and the bet number), within this betting series, (look at the probabilities of flipping a coin as posted before) with this knowledge you will be able to adjust the size of the Kelly Opt. and apply this to your next bet. Always remembering that you need to have a higher avg bet size on winning bets then on losing bets.


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