24th July 2006, 04:25 PM
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Member
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Join Date: Jan 1970
Location: Sydney
Posts: 402
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Crash,
Let me try to answer your horse question first.
The assumption is that all 10 runners have equal chances.
The chance of your 3 picks filling 1st, 2nd and 3rd in any order is the spreadsheet expression:
=1/combin(10,3)
=1/120
The Peter gamble is actually a variation of the infernal St Petersburg Paradox. I only found out about that today, and I'll comment if I can work my way through it.
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