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Originally Posted by AssumeTheCrown
Problem 2:
What is the probability of B overtaking A?
8.9844%
Will leave the general solution for someone else.
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8.9844% = Agreed
Problem 3 can keep for now.
Round to 9% as we move to Problem 4:
This should be quicker and easier than the others, so therefore there should be an avalanche of responses.
And the answer seems counter-intuitive to me.
Problem 4:
4 Rounds remaining.
Team G is 2 games out of the 8.
It is directly below 5 Teams all equal on wins. A, B, C, D, & E.
G has an equal 9% chance of finishing ahead of any one of the other 5.
The only 2 possibilities are:
- G fails to make the 8
- G makes the 8, kicking out 1 of A - E
So what is the probability of G making the 8?
In case I'm being too subtle, this hypothetical problem is moving quite close to the current real AFL one.