Thats ok send it thru I'll scan over it for you.

Moee you need to use track records with a thing called "marginal speed" this is the rate of deceleration for every additional metre raced.

consider Meadows and Traralgon split times
We know this is straight speed.
Meadows split measures 70.55 metres 4.94 TR
Cranbourne measures 77.4 metres 5.28 TR

77.4 -70.55 = 6.85
5.28 - 4.94 = .340
20.147
the reciprocal of the above number is 1/20.147 = .049635
additional distance 6.85 multiplied by .049635 = +.3399

So if you repeated the above for every track and recorded the reciprocal (.049635) number you would end up with a Universal number that can compute every straight split distance without any problems at all.

When we do the turns its just a matter of using a centripetal formula which invloves just knowing the radius of the turns.