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Old 14th April 2012, 07:31 PM
woof43 woof43 is offline
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Join Date: Jan 1970
Posts: 696
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Moee,
If you understand this you have done well, then you can start calculating all the sectional distances.

COMPUTATION OF SECTIONAL DISTANCES FOR GREYHOUNDS
MEADOWS 525 TR =29.45 SECT RECORD =4.93

1. BASIC COMPUTATIONS:
ADJ TM 29.45 MINUS 1.11 = 28.34
MAX SPD 525 DIV BY 28.34 = 18.53
MAX TIM 29.45 MINUS 3.9 = 25.55
MAX DST 18.53 TIMES 25.55 = 473.32
ACC DIST 525 MINUS 473.32= 51.68

PROOF
MAX SPEED = 18.53

0.9 TIMES 18.53 = 16.67
1.89 TIMES 18.53 = 35.01
(SECT TIME MINUS 4.93-3.90)=1.03 TIMES 18.53 = 19.08
SUM 16.67+35.01+19.08= SECTIONAL DISTANCE 70.77 METRES

ACCELERATION CONSTANT
AVG SPEED: % MAX SPEED DISTANCE: AS % OF MAX SPEED
.9 T .99 T .9 T .99 T
0.450 0.995 0.90 1.89
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