If one reads the rule at the beginning of this thread it clearly states that one deletes the weakest runner of each group of 4 so that one ends up with 3 in each group.

e.g. TAB Nos. 127/346. O/L 3x3=9
OR
1278/34 O/L4X2=8

The idea is to end up with 6 runners out of the 1-8 TAB Nos
and sector them off out of the original sequence Nos. 1278/3456 (now delete one No. from each sector of 4 so that you end up with 3x3

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Cheers.