View Single Post
  #6  
Old 9th June 2023, 09:46 PM
angrymob angrymob is offline
Member
 
Join Date: Jan 1970
Location: perth
Posts: 19
Default

HI Shaun thanks for sending info this is what came up when trying to run the file
unhandled exception in the script

Traceback (most recent call last):
File "R2P.py", line 1272, in
File "R2P.py", line 73, in timedate
File "R2P.py", line 82, in get_race_meetings
File "json\__init__.py", line 357, in loads
File "json\decoder.py", line 337, in decode
File "json\decoder.py", line 355, in raw_decode
json.decoder.JSONDecodeError: Expecting value: line 1 column 1 (char 0)

I put it in ai chat this was answer
he error message you provided indicates a JSONDecodeError, which means there is an issue with decoding JSON data. The error specifically states that it was expecting a value at line 1, column 1 (char 0). This typically occurs when the JSON data you are trying to parse is empty or invalid.

To fix this error, you can try the following steps:

Verify the JSON data: Check the source of the JSON data and ensure that it is valid. Make sure the JSON data is not empty and follows the correct JSON syntax.

Validate the JSON data: Use a JSON validator or an online JSON formatter to validate the structure and syntax of the JSON data. This can help identify any potential errors or inconsistencies.

Ensure the file or API is providing the expected JSON data: If you are reading the JSON data from a file or an API, double-check that the source is providing the correct data. Confirm that the data being retrieved is not empty or corrupted.

Handle exceptions: Surround the code block where you are parsing the JSON data with a try-except block to catch the JSONDecodeError. This way, you can handle the error gracefully and provide appropriate feedback or fallback behavior in case of an error.

Here's an example of how you can use a try-except block to handle the JSONDecodeError:

python
Copy code
try:
# Code to parse JSON data
# ...
except json.decoder.JSONDecodeError as e:
print("Error decoding JSON data:", e)
# Handle the error or provide fallback behavior
# ...
By following these steps and handling the JSONDecodeError appropriately, you can troubleshoot and fix the issue in your code.
I don't understand any of it but once again thanks for replying and sending info
Ron
Reply With Quote