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#1
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Formula Help in extracting horse last 4 starts
Can any one please help......l've paste the form guide but can not separate the 4 placings ...eg l have the placing of 1356 in Col.B ..R3 would like to put 6 in Col.C R3..5 in E..3 in F...1 in G.... l've tried this formula but only goes to 3 ...numbers.....=IF(LEN($B3)=2,"",IF(LEN($B3)=1,"",LEFT($B3,1)))....=IF(LEN($B3)=1,"",IF(LEN($B3)=3,MID($B3,2,1),LEFT($B3,1)))
=RIGHT($B3,1)..Thanking you Blkscout |
#2
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anything in column d ?
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#3
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That looks over complicated.
Just use a combination of IF, LEFT and RIGHT. 1356 is your value. So for COL B you want COLB = IF (LEN(B3) = 4, LEFT(B3,1), "") COLC = IF (LEN(B3) >=3, LEFT(RIGHT(B3,3),1),"") COLD = IF (LEN(B3) >=2, LEFT(RIGHT(B3,2),1),"") COLE = IF (LEN(B3) >=1, RIGHT(B3,1),"") Seems easy enough. My sytax might be slightly off but the logic should be right. Adjust to where you want to put them. |
#4
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b3= 1356
c3= =MID(B3,LEN(B3),1) d3= =MID(B3,LEN(B3)-1,1) e3= =MID(B3,LEN(B3)-2,1) f3= =MID(B3,LEN(B3)-3,1) is that whatyou mean |
#5
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even tidier:
b3= 1356 c3= =iferror(MID(B3,LEN(B3),1),"") etc d3= =MID(B3,LEN(B3)-1,1) e3= =MID(B3,LEN(B3)-2,1) f3= =MID(B3,LEN(B3)-3,1) |
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