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![]() I am having problem accepting the Harville method for calculating Exactas.
I have 2 animals from the Field I wish to calculate the Chances of the Exacta occuring #1 is $2.50 #2 is $11 The Exactas work out as 1 - 2 is $16.80 and for 2 - 1 is $25.20 It seems to me that the Chance of the Rougher animal beating the more Favoured animal is too close to the Chances of the Favoured animal beating the Roughie. If I could calculate each animals Chances of winning the race, and also calculate each animals chances of running second, is there a Formula I could use that would give me a more accurate assessment of the Exacta occuring. Last edited by moeee : 31st May 2011 at 01:44 PM. Reason: math error |
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