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Old 15th November 2005, 04:07 PM
crash crash is offline
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Join Date: Jan 1970
Location: gippsland lakes/vic
Posts: 5,104
Default The Cancellation staking system

For those who like staking systems this is about as good as they get:

The concept behind this system is that in the long run two events of roughly equal probability will happen roughly the same number of times. This system depends on this happening in the short run. The more money you wish to put up, the longer into the long run you can afford to go, thus increasing your odds of a winning session, but at the risk of losing more.

1. Start by writing on a piece of paper ten 1s in a row (1 1 1 1 1 1 1 1 1 1). Each number will represent a betting unit. When all numbers have been crossed off the paper you will have won 10 units.
2. For each bet wager the sum of the number on the left and the number on the right, unless there is only one number left in which case you bet that number.
3. If you win cross off both numbers.
4. If you lose place the sum at the end on the right.
5. If the bankroll you decided to risk at the beginning is not enough to bet the sum of the left and right numbers then:
5A. If your bankroll can cover the number on the left then wager that. If you win then cross off the left number. If you lose then add to the left number what you lost.
5B. If your bankroll can not cover the number on the left then bet whatever is left of your bankroll. If you win then deduct from the number on the left what you won.
6. Keep repeating these steps until you either cross off all numbers or exhaust the bankroll you decided initially to risk.

Here is an example:
You start with 1 1 1 1 1 1 1 1 1 1.
You then wager two units and win, cross off the 1 on the left and right, leaving 1 1 1 1 1 1 1 1.
You then wager another two units and lose, adding a 2 to the right, leaving 1 1 1 1 1 1 1 1 2.
You then wager three units (1+2) and lose again, adding a 3 to the right, leaving 1 1 1 1 1 1 1 1 2 3.
You then wager four units (1+3) and win, crossing off the 1 on the left and the 3 on the right, leaving 1 1 1 1 1 1 1 2 .

The theory is that by crossing off two numbers for a win and adding only one for a loss you will eventually cross off all the numbers.

Cheers.

Last edited by crash : 15th November 2005 at 04:27 PM.
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